Python 通过接受 5 位数字作为输入进行图案打印

Question

We were asked to write python program to read 5 digit number for example if the user entered 12345 the result should be:

1
12
123
1234
12345

I have written something like below but it's not working and appending the output to earlier digit.

n = '12345'
for i in range(len(n)+1):
    for j in range(i+1):
         print(n[0:j],end = "")
    print()

The wrong output is

1
112
112123
1121231234
112123123412345

Please help in achieving the output in above format mentioned. Thanks in advance!

Answer 1

You can use

for i in range(1, len(n) + 1):
    print(n[:i])   

There's no need for a nested loop here.

Answer 2

your answer has four errors

error 1: range of i should be 1 to len(n)+1 if u take zero it will print space in first line,for avoiding that start ur range (1,len(n)+1)

error 2: range of j should be i only cause i+1 is sending it out of range

error 3: as u are doing slicing of string u have to pass the the j only cause u are slicing the string from one index number to other....but u just need the letter of that index

error 4: in the last line u have to print("\r") so that it will go to new line

n = '12345'
for i in range(1,len(n)+1):
    for j in range(0,i):
        print(n[j],end = "")
    print("\r"

output will be like this:

 <pre> 1 12 123 1234 12345 </pre>