如何按行值过滤此 pandas dataframe？

Question

This is my pandas dataframe

print(df)

Name       Sale Value
ADAMSAE    1475000
BAKERDE    1412000
CLARKAE    1480450
DAVISDE    1483700
EVANSAE    1285000

Can anyone tell me how can I filter the row by its Name columns last two character of the string like this--- ADAMSAE BAKERDE by AE DE

Expected dataframe------

print(AE_df)
Name       Sale Value
ADAMSAE    1475000
CLARKAE    1480450
EVANSAE    1285000

and

print(DE_df)
Name       Sale Value
BAKERDE    1412000
DAVISDE    1483700

Answer 1

You can use df['Name'].str[-2:] .

output:

0    AE
1    DE
2    AE
3    DE
4    AE
Name: Name, dtype: object

To make groups automatically:

d = dict(list(df.groupby(df['Name'].str[-2:])))

output:

{'AE':       Name  Sale Value
 0  ADAMSAE     1475000
 2  CLARKAE     1480450
 4  EVANSAE     1285000,
 'DE':       Name  Sale Value
 1  BAKERDE     1412000
 3  DAVISDE     1483700}

Answer 2

you could use endswith , like:

df[df.Name.str.endswith('AE')]