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C++ 左移操作位操作

[英]C++ Left Shift Operation Bit Manipulation

I am not able to get why it is giving negative after certain point.我不明白为什么它在某个点后给出负数。 Also I am using long long to prevent overflow.我也使用 long long 来防止溢出。

Code代码

#include <iostream>
using namespace std;

int main() {
    
    for(long long i=0;i<64;i++){
        cout << 1LL*(1<<i) << " ";
    }
    
    return 0;
}

Output Output

1 2 4 8 16 32 64 128 256 512 1024 2048 4096 8192 16384 32768 65536 131072 262144 524288 1048576 2097152 4194304 8388608 16777216 33554432 67108864 134217728 268435456 536870912 1073741824 -2147483648 1 2 4 8 16 32 64 128 256 512 1024 2048 4096 8192 16384 32768 65536 131072 262144 524288 1048576 2097152 4194304 8388608 16777216 33554432 67108864 134217728 268435456 536870912 1073741824 -2147483648 
1 << i

..in the above line, 1 is an int and i is a long long . ..在上面的行中, 1是一个int而 i 是一个long long So to fix your issue you can cast to a long long as such:因此,要解决您的问题,您可以long long使用:

#include <iostream>
using namespace std;

int main() {

    for (long long i = 0; i < 64; i++) {
        cout << 1LL * (static_cast<long long>(1) << i) << " ";
    }

    return 0;
}

This will allow you to go to higher values.这将允许您将 go 设置为更高的值。

You can also use 1LL ( 1 long long ) instead of casting:您还可以使用1LL ( 1 long long ) 而不是强制转换:

cout << 1LL * (1LL << i) << " ";

..with this you can remove 1LL * : ..有了这个你可以删除1LL *

cout << (1LL << i) << " "; // Brakcets are required

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