自动启动 android 10 中的应用程序

Question

I am trying to launch an application once my android is finished booting. @user:3801327 has stated You could do this in several ways:

Have your app act as launcher ( set launcher declarations in manifest and set it as default launcher) Modify your default launcher (eg Launcher3) to start the app when the launcher starts. Modify SystemUI app to start your app when it first starts. Modify SystemServer or one of the system services ( eg ActivityManagerService ) to start your app when the correct boot phase is reached (eg PHASE_BOOT_COMPLETED )

I would like to modify the launcher to make this happen by decompiling it and adding the autostart command to the launcher but I am unsure how to do that. Alternatively, I am fine doing it in init.rc but for some reason it isn't running my script (test.sh). If someone can explain either of these options I would be grateful.

Answer 1

You could try running it with activity manager in the init script somewhere on early boot Im guessing? Use the following command

am start -n com.you.package/.your.activity -a android.intent.action.VIEW

for example
am start -n com.example.app/.ui.activities.login.LoginActivity -a android.intent.action.VIEW

Im not sure if init script supports this so you could just make a bash script which runs this command and call that bash script in your init script

Answer 2

Given I was working on Android 10 and it has different security then what I am used to the easiest solution for me was to modify the launcher to boot the application when it the launcher launches.