如何在python3中给用户输入

Question

n=input("enter the no:")
check(test_list,n)

def check(test_list,n):
    for i in test_list:
        if(i==n):
             print("yes in a list")
             continue
        else:
            continue

I had written the simple code to check if a no. exists in a list or not, but while taking user input I"m not getting any results after providing input value n.

Why is so?

Answer 1

In your code the first line should be corrected as n=int(input("enter the no:")) .

In python it takes the inputs as strings . Think if you are giving the input as 3. Then the variable n stores the value "3"( not the value 3 ). You should need to know 3 == "3" is False .

Therefore, when you are taking the input you should convert that string input to the int . To do that we use int() method. The int() method converts the specified value into an integer number

n=int(input("enter the no:")) check(test_list,n)

def check(test_list,n):
    for i in test_list:
        if(i==n):
             print("yes in a list")
             continue
        else:
            continue

Answer 2

You were not getting any results because the input() function always returns a string. For this reason, we need to convert it to an Integer before passing it on into the function, and I did with n=int(input()) .

n=int(input("enter the no:"))

def check(test_list,n):
    for i in test_list:
        if(i==n):
             print("yes in a list")
             continue
        else:
            continue

check((1,2,3),n)