Javascript 正则表达式删除小数点后的尾随零

Question

I know this has been asked many times and I did find a solution, value.replace(/^([\d,]+)$|^([\d,]+)\.0*$|^([\d,]+\.[0-9]*?)0*$/, "$1$2$3") .

But... I'm no regex expert so I'm just curious as to why this doesn't work /[\.0]+$/ ... 10 should return 10 but I just can't figure out how to exclude whole numbers that end with 0s.

1.7500, 1.1010, 1.0000, 10

1.75, 1.101, 1, 1

Answer 1

You might shorten the pattern to match either a dot with only zeroes, or use a non greedy match for the digits with a capture group and match optional trailing zeroes.

If you want to match digits and comma's the first \d+ can also be [\d,]+ as you already have in your pattern.

If there should be at least a single digit after the dot, then the quantifier can be a plus .\d+?

^(\d+)(?:\.0+|(\.\d*?)0+)$

See a regex 101 demo .

 [ "1.7500", "1.1010", "1.0000", "10" ].forEach(s => console.log(s.replace(/^(\d+)(?:\.0+|(\.\d*?)0+)$/, "$1$2")) );