Java 字符串比较，按字母顺序打印两个不同的字符串输入

Question

We are learning compareTo() method and equals() method, but I am unsure how to properly print the words in alphabetical order.

I have 2 Strings:

String firstString;
String secondString;

that are assigned values (elsewhere).

I have tried:

System.out.println(firstString.CompareToIgnoreCase(secondString)); 

but am only getting integers in my output as opposed to full words.

Answer 1

As this is homework, I'll only address your stumbling block.

As per the documentation , compareToIgnoreCase() (and more generally, compareTo() ) returns an integer, either negative, zero or positive, depending on whether the first parameter's order is less than, the same or greater respectively than the second parameter.

You'll need to check the result of compareToIgnoreCase() , then print based on that, for example:

if (firstString.compareToIgnoreCase(secondString) > 0) {
    // do something
} else {
    // do something else
}

Answer 2

For those taking the same class, this solves the requirements for the question:

  if (firstString.compareTo(secondString) < 0) {
     System.out.println(firstString + " " + secondString);
  }
        
  else {
     System.out.println(secondString + " " + firstString);
  }