[英]Typescript - Remove undeclared properties of a class
I am trying to create a DTO class. But I am having issues finding a proper way to exclude undeclared properties.我正在尝试创建一个 DTO class。但是我在寻找排除未声明属性的正确方法时遇到了问题。 So if some one tries to create a DTO class and adds extra properties that are not declared inside the class then those properties should be ignored and not be added.因此,如果有人试图创建 DTO class 并添加未在 class 中声明的额外属性,则应忽略且不添加这些属性。
import { IsString, MinLength } from 'class-validator'
export class CreateUserDto {
@IsString()
email: string
@IsString()
@MinLength(6)
password: string
@IsString()
firstname: string
@IsString()
lastname: string
constructor (payload: any) {
const dto = Object.assign(this, payload)
console.log(dto)
}
}
For only 4 fields, I'd rather manually type out 4 lines to assign them each, but I guess if you have more DTO's with a lot more fields it could help with a more versatile method.对于只有 4 个字段,我宁愿手动输入 4 行来分别分配它们,但我想如果你有更多的 DTO 和更多的字段,它可以帮助使用更通用的方法。
Here I've used Object.entries
and Object.fromEntries
along with a filter to exclude properties we don't need:在这里,我使用Object.entries
和Object.fromEntries
以及一个过滤器来排除我们不需要的属性:
const dto = Object.assign(this, Object.fromEntries(Object.entries(payload).filter(([k]) => keys.includes(k))))
And keys
would be something like: keys
会是这样的:
["email", ...]
You can also make this a function for reusability or even a decorator too.您也可以将其设为 function 以实现可重用性,甚至是装饰器。
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