C 将文件中的单词存储到动态分配的数组中，存储不正确

Question

If I am dynamically allocating an array of pointers to chars(strings). why I cant place the content of the *word inside a given position in my array like so array[i] = word or array[i] = *word .

I want to split and store the words in a file into a dynamically allocated array. Is this the right direction or is it done through a 2D array.

int main(int argc, char *argv[]) {
   FILE *file = fopen(argv[1], "r");

   fseek(file, 0, SEEK_END);
   size_t size = ftell(file);
   fseek(file, 0, SEEK_SET);
   char *array = malloc(size * sizeof(char)+10);
   char *array2 = malloc(size * sizeof(char)+10);
   fread(array, 1, size, file);
   array[size] = '\0';
   char *word;
   word = strtok (array, " ,.-");
   int i = 0;
   while (i <= 9 && word != NULL ){
      for(i = 0; i < 10; i++) {
         array[i] = *word;
         strcpy(&array2[i], word);
         word = strtok (NULL, " ,.-");
      }
      fclose(file);
   }
   for (i = 0; i < 10; ++i)
      printf("array[%d] = %c\n", i, array2[i]);
   free(array);
   free(array2);
   fclose(file);
   return 0;
}

text to read.

This free test evaluates how well you understand what you

current output

array2[0] = T
array2[1] = f
array2[2] = t
array2[3] = e
array2[4] = h
array2[5] = w
array2[6] = y
array2[7] = u
array2[8] = w
array2[9] = y

What Id like to get.

array2[0] = The
array2[1] = free
array2[2] = test
array2[3] = evaluates
array2[4] = how 
array2[5] = well
array2[6] = you
array2[7] = understand
array2[8] = what
array2[9] = you

Answer 1

You need two different arrays

The first is the buffer you read the data into - lets call that 'buffer', its a char*

The second is an array of pointers to 'strings' - lets call that 'words' its a char**

int main(int argc, char* argv[]) {
    FILE* file = fopen("dict.txt", "r");

    fseek(file, 0, SEEK_END);
    size_t size = ftell(file);
    fseek(file, 0, SEEK_SET);
    char* buffer = malloc(size * sizeof(char) + 10);
    char** words = malloc(sizeof(char*) *  10);
    fread(buffer, 1, size, file);
    buffer[size] = '\0';
    char* word;
    word = strtok(buffer, " ,.-");
    int i = 0;
    while (i <= 9 && word != NULL) {
        for (i = 0; i < 10; i++) {
            words[i] = word;
            word = strtok(NULL, " ,.-");
        }
        fclose(file);
    }
    for (i = 0; i < 10; ++i)
        printf("array[%d] = %s\n", i, words[i]);
    free(buffer);
    free(words);
    fclose(file);
    return 0;
}

I will comment on the complete lack of tests to check if anything worked, PLus I have hardcede to 10 words - since you have done that in the loop it seems.

Also note that the 'words' array if full of pointers to the 'buffer'. If you delete or change 'buffer' 'words' will be invlaid