包括隐藏文件在内的所有内容的 Glob 模式

Question

I try to get a glob pattern which includes every file in every subdirectory, but I can't figure out how to include hidden files.

Example, all those should match:

.git
.github/workflow.yml
index.js
src/index.js
src/components/index.js

This works for all files with name and extension, but leaves out hidden files:

**/**

More specific background: I want so make an archive with all files except node_modules (and potentially some others), using the archiver library.

archive.directory("???", {
    ignore: ["node_modules/", ...some other files],
});

Answer 1

The best way is probably to use two separate patterns, one of which matches the hidden files, and one which matches the non-hidden files. One way to do this is .* * . However, this matches the directory itself . and parent .. as well, which is usually not what you want.

A pattern which avoids this problem is .??* * . Suppose you have the following files in your directory.

file1  file2  .hidden

As you can see in the example below, this glob pattern matches both hidden files and non-hidden files, but not the current directory or its parent.

$ ls -l .??* *
-rw-r--r-- 1 amy users 0 Jul 30 18:00 file1
-rw-r--r-- 1 amy users 0 Jul 30 18:00 file2
-rw-r--r-- 1 amy users 0 Jul 30 18:00 .hidden