我想将十六进制字节数组转换为字符串格式的十六进制

Question

I want to convert byte format to string format. The conversion target is as follows. \xb9S\xfc\x81\xe4\xa2\xb9\x92\x8d\xbb1\xfe\xb9\xa1&\x16\...... Convert to string format.

For example, b'\xfc\x81\xe4\xa2\xb9\x92' #type:bytes -> "FC 81 E4 A2 B9 92" #type:str

No matter how much I searched, I couldn't find the module by myself. Any help would be appreciated.

Answer 1

This is implemented in the standard lib

Starting with python 3.5, you got this:

val = b'AAAAA'
print(val.hex())
    
# prints '4141414141'

With python 3.8+, you can also specify a separator:

val = b'AAAAA'
print(val.hex(' '))
    
# prints '41 41 41 41 41'

if you absolutely want them in uppercase, you can call upper() on the result.

Answer 2

def format_bytes_as_hex(b: bytes) -> str:
    h = b.hex()
    return ' ' .join(f'{a}{b}'.upper() for a, b in zip(h[0::2], h[1::2]))


Test:
format_bytes_as_hex(b'\xfc\x81\xe4\xa2\xb9\x92')
'FC 81 E4 A2 B9 92'