[英]How to pass function as method parameter?
I have 2 methods for getting average age of woman, and second for getting average age of man.我有两种获取女性平均年龄的方法,第二种获取男性平均年龄的方法。 I need to do one method to agregate this 2 methods.
我需要做一种方法来聚合这两种方法。
This method as first parameter should have list of person, and as a second parameter function what will decide if we are looking for man or woman average age.这个方法作为第一个参数应该有人员列表,作为第二个参数 function 什么将决定我们是在寻找男人还是女人的平均年龄。
This is my methods:这是我的方法:
public double getMenAverageAge(List<Person> personList){
return Optional.ofNullable(personList)
.orElseGet(ArrayList::new)
.stream()
.filter(Objects::nonNull)
.filter(p -> !Boolean.parseBoolean(String.valueOf(p.getFirstName().endsWith("a"))))
.mapToDouble(Person::getAge)
.average()
.orElse(0);
}
public double getAverageWomenAge(List<Person> personList){
return Optional.ofNullable(personList)
.orElseGet(ArrayList::new)
.stream()
.filter(Objects::nonNull)
.filter(p-> Boolean.parseBoolean(String.valueOf(p.getFirstName().endsWith("a"))))
.mapToDouble(Person::getAge)
.average()
.orElse(0);
}
Any ideas?有任何想法吗?
Predicate<Person> p = p-> Boolean.parseBoolean(String.valueOf(p.getFirstName().endsWith("a")));
Predicate<Person>
is just a type. Predicate<Person>
只是一种类型。 There's not much difference between the above and String x = "hello";
上面和
String x = "hello";
没有太大区别. . You can make a method that accepts that type as param:
您可以制作一个接受该类型作为参数的方法:
public double getAverageAge(List<Person> list, Predicate<Person> filter) {
return list
.stream()
.filter(filter)
.mapToDouble(Person::getAge)
.average()
.orElse(0);
NB: You have null tourette, it's a formula for writing lots of code that is impossible to test.注意:您有 null 图雷特,它是编写大量无法测试的代码的公式。 Don't do it.
不要这样做。 Love the NPE.
喜欢 NPE。 The correct response to someone invoking this method passing in
null
for a list is to crash with an NPE: null is best treated as 'unset' / 'unknown', and it is not possible to get the average age of an unknown list.对有人调用此方法传递
null
的列表的正确响应是与 NPE崩溃:null 最好被视为“未设置”/“未知”,并且不可能获得未知列表的平均年龄。 The answer is not 0. The answer is ¯\ (ツ) /¯.答案不是0。答案是¯\ (ツ) /¯。
Similarly, if somehow a null
got into your list of persons, then the age of that person is also unknown.同样,如果
null
以某种方式进入了您的人员列表,那么该人的年龄也是未知的。 It is not possible to determine the average age of a batch of persons when one of the persons in there is a complete unknown, again, just NPEing is in fact the right response.当其中一个人完全未知时,无法确定一批人的平均年龄,同样,NPEing 实际上是正确的反应。
The best way to deal with null in java is to use the tools to your advantage: If the NullPointerException is in fact the best thing that could happen, you're doing it right.处理 java 中的 null 的最佳方法是使用对您有利的工具:如果 NullPointerException 实际上是可能发生的最好的事情,那么您做对了。
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