在 python 中使用正则表达式从多行变量中查找匹配的字符串

Question

I am trying to grab some data from a variable. It is in a multiline. Currently, my output is empty. Thanks in advance.

    test = re.findall("0x\sN/A",newMessage,re.MULTILINE)
    print ("test ", test)

Sample Data:

🆕 New token

Version: V2

Pair: WBNB-WCH
Liquidity: 22.0000 BNB ($8284.1997)   #-- data to grab
ℹ️ Transaction

Name: WCH
Total Supply: 1,000,000,000 WCH
Token Price: 0.0000 BNB ($0.0000)     #-- data to grab

Holders: 1
Transfers: 1

⛓ BscScan

🥞 Swap on PancakeSwap

➡️ poocoin.app

0xe61cDdDdF26Ac94C214C981FA012AcA805ea4b4D     #-- data to grab
-----------------------------------
Our Chat - YourCryptoHelperChat
Our Main Info Channel - YourCryptoHelper

Current Output:

test  []

Wanted Output:

0xe61cDdDdF26Ac94C214C981FA012AcA805ea4b4D
Liquidity: 22.0000 BNB ($8284.1997)
Token Price: 0.0000 BNB ($0.0000)

Answer 1

I assumed your case is simple. So this is simple solution to find:

• Starts with Liquidity:
• Starts with Token Price:
• Starts with 0x

import re
find = r"^(Liquidity: .+|Token Price: .+|0x.+)"
test = re.findall(find, value, re.MULTILINE)
for ret in test:
  print (ret)

Result:
Liquidity: 22.0000 BNB ($8284.1997)
Token Price: 0.0000 BNB ($0.0000)
0xe61cDdDdF26Ac94C214C981FA012AcA805ea4b4D

https://regex101.com/r/1fqORj/1

https://trinket.io/python/99b59d62b8

Answer 2

regex = r"Liquidity: ([^#]*).*Token Price: ([^#]*).*(0x[\da-fA-F]{40})"
matches = re.finditer(regex, test_str, re.MULTILINE | re.DOTALL)