[英]Cannot Convert in_addr to Unsigned Int in Socket Programming for Linux
I'm building a reverse echo server in TCP using c++.我正在使用 c++ 在 TCP 中构建反向回显服务器。
My problem occurs when I run my client.我的问题发生在我运行客户端时。
When I compile my client.cpp, I get this error:当我编译我的 client.cpp 时,我得到这个错误:
error: cannot convert ‘in_addr’ to ‘in_addr_t {aka unsigned int}’ in assignment
serverAddress.sin_addr.s_addr = *((struct in_addr*)host->h_addr);
This is my code for creating a connection:这是我创建连接的代码:
serverName = argv[1];
struct sockaddr_in serverAddress;
struct hostent* host;
host = gethostbyname(serverName);
memset(&serverAddress, 0, sizeof(serverAddress));
serverAddress.sin_family = AF_INET;
serverAddress.sin_addr.s_addr = *((struct in_addr*)host->h_addr);
serverAddress.sin_port = htons(serverPort);
memmove(&serverAddress.sin_addr.s_addr, host->h_addr_list[0], host->h_length);
connectValue = connect(clientSocket, (struct sockaddr*)&serverAddress, sizeof(serverAddress));
Am I missing something?我错过了什么吗?
You are trying to assign a whole in_addr
struct instance to a single integer. That will not work.您正在尝试将整个in_addr
结构实例分配给单个 integer。那是行不通的。
The sockaddr_in::sin_addr
member is an in_addr
struct, and the in_addr::s_addr
member is the actual IP address. sockaddr_in::sin_addr
成员是一个in_addr
结构, in_addr::s_addr
成员是实际的 IP 地址。 Just drop the s_addr
part to assign the whole in_addr
struct as-is:只需删除s_addr
部分即可按原样分配整个in_addr
结构:
serverAddress.sin_addr = *((struct in_addr*)host->h_addr);
Otherwise, you can memcpy()
(or, in your example, memmove()
) the in_addr
struct into the sin_addr
member as a whole.否则,您可以将memcpy()
(或者,在您的示例中为memmove()
)将in_addr
结构作为一个整体放入sin_addr
成员中。 You are trying to copy/move to its s_addr
member instead, so just drop that:您正在尝试复制/移动到其s_addr
成员,所以只需删除它:
memcpy(&serverAddress.sin_addr, host->h_addr, host->h_length);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.