如何从扩展代码中检测 VSCode 面板可见性？

Question

I would like to create an extension to toggle all the currently visible panels by a single shortcut. So something like the command "Hide/show All Tool Windows" from JetBrains IDEs, which I think is still missing in VS Code.

VS Code can have up to 3 panels visible:

• Sidebar (the left-side panel)
• Panel (the bottom panel)
• AuxiliaryBar (the new right-side panel)

For that purpose, I need to detect the current state of all the panels from the extension code, so I can toggle only the panel(s) which are currently visible.

But alas I can't find it anywhere in the documentation. This page ( https://code.visualstudio.com/api/references/when-clause-contexts ) contains several variables like sideBarVisible , but I really don't get how to access those context variables from the vscode namespace which you can access from the extension.

import * as vscode from 'vscode';

So, is there a way how to detect if the panel is open or closed from the extension code?

Answer 1

Do you really need to know whether they are open or closed? Can't you just toggle them all?

vscode.commands.executeCommand('workbench.action.toggleSidebarVisibility')
vscode.commands.executeCommand('workbench.action.togglePanel')
vscode.commands.executeCommand('workbench.action.toggleAuxiliaryBar')