使用正则表达式在 Java 中验证密码

Question

I need a regular expression to check that if a password contains:

• [1,6] uppercase/lowercase characters
• [1,10] digits
• [0,1] special characters

I tried multiple approach, but without success. I don't know if I can do this verify with regex. The most accurate pattern is: ^(?=(.*[a-zA-Z]){1,6})(?=(.*[0-9]){1,10})(?=(.*[.@#$%^&*()\-__+,]){0,1})

But it don't work good when I have more than 6 char, 10 digits or 1 special character.

Could anyone help me?

Answer 1

I might not use a single regex pattern, but would instead use multiple checks. For example:

String password = "ABC123@";
int numChars = password.replaceAll("(?i)[^A-Z]+", "").length();
int numDigits = password.replaceAll("\\D+", "").length();
int numSpecial = password.replaceAll("[^!@#$%^&*()_+.-]", "").length();

if (numChars >=1 && numChars <= 6 && numDigits >= 1 && numDigits <= 10 &&
    numSpecial <= 1) {
    System.out.println("password is valid");
}
else {
    System.out.println("password is invalid");
}