我如何使用正则表达式拆分此字符串

Question

I have a string similar to:

"'a b | c'\,\,\,  'd | e f' ,,, 'g | h"

I want to use re.split to get the following list:

["a b|c", "d|e f", "g|h"]

I have tried the following but do not get the output i want, essentially i need to get rid all everything aside from the letters and the pipe operator, and split. One issue is that sometimes both ' and " are used:

re.compile(r'[\"\',][\W+]', re.UNICODE).split(txt.lower())

Answer 1

Remove the spaces around |as a separate step after splitting.

split = re.compile(r'[\"\',][\W+]', re.UNICODE).split(txt.lower())
cleaned = [re.sub(r'\s*\|\s*', '|', x) for x in split]

Answer 2

I don't think you can just use split . You probably can't get rid of the first quote, or will end up with an empty first item.:

Here is one attempt, but it fails to remove the initial ' :

re.split(r"(?<=.)'[^']+'", txt)

output: ["'ab | c", 'd | e f', 'g | h'] ["'ab | c", 'd | e f', 'g | h']

An alternative with findall :

re.findall(r"'([^']+)'?", txt)

output: ['ab | c', 'd | e f', 'g | h'] ['ab | c', 'd | e f', 'g | h']