[英]Find substring in pandas dataframe and save in new column
I have a dataframe with approx.我有一个 dataframe 大约。 10,000 rows and 10 columns. 10,000 行和 10 列。 And I have a string, which I want to search for in the dataframe, called 'atmosphere'.我有一个字符串,我想在 dataframe 中搜索它,称为“atmosphere”。 This string can only be found once in a row.该字符串连续只能找到一次。 I want to keep only the cells that contain this string, but with their whole content, and save them in a new column.我只想保留包含此字符串的单元格,但保留它们的全部内容,并将它们保存在新列中。 I already found the following solution, but it only gives me back "True" (when cell contains string) or "False" (when it does not).:我已经找到了以下解决方案,但它只返回“True”(当单元格包含字符串时)或“False”(当它不包含字符串时)。:
df.apply(lambda col: col.str.contains('atmosphere', case=False), axis=1)
Output:
col_1 col_2 col_3 col_4 ...
1 True False False False
2 False True False False
3 True False False False
...
How can I get from this, to this?:我怎样才能从这个到这个?:
new_col
1 today**atmosphere**is
2 **atmosphere**humid
3 the**atmosphere**now
If you already have your result, you can simply stack
it:如果你已经有了你的结果,你可以简单地stack
它:
df = pd.DataFrame({"a":["apple", "orange", "today atmosphere"],
"b":["pineapple", "atmosphere humid", "kiwi"],
"c":["the atmosphere now", "watermelon", "grapes"]})
a b c
0 apple pineapple the atmosphere now
1 orange atmosphere humid watermelon
2 today atmosphere kiwi grapes
print (df[df.apply(lambda col: col.str.contains('atmosphere', case=False), axis=1)].stack())
0 c the atmosphere now
1 b atmosphere humid
2 a today atmosphere
dtype: object
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