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通过 X 和 Y 获取索引

[英]Get Index by X and Y

There's a way to get X and Y based on Index like有一种方法可以根据索引获取 X 和 Y

x = index % columns;
y = index / columns;

How can I reverse this and get Index based on X and Y?我怎样才能扭转这一局面并获得基于 X 和 Y 的索引?

Assuming we're dealing with integers here, if you have the following code:假设我们在这里处理整数,如果您有以下代码:

x = index % columns; // get the remainder of dividing index by columns 
y = index / columns; // get the result of dividing index by columnsn

Then the reverse would be:那么反过来就是:

index = y * columns + x;

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