在 SQL 中使用 Case When 返回不同的值

Question

I would like to join various table and convert some column values from integer to text like below case. Let's say I have Type_ID: 1, 2, 100, 200, 300, .....

If the Type_ID are 1 and 200, then it will print out High and Good respectively. But if the Type_ID are not 1 and 200, I want it to return original integer value. How can I do that? Thanks.

SELECT A.AID, 
CASE WHEN B.Type_ID = '1' THEN 'High' WHEN B.Type_ID = '200' THEN 'GOOD' ELSE (Print Original number value) END AS 'Type'
FROM A, B
WHERE A.AID = B.AID

Expected Result:

AID	Type
1	High
2	499
3	Good
4	Good
5	100
6	300

Answer 1

If I understand correctly, the else value should just be the Type_ID :

SELECT A.AID, 
       CASE B.Type_ID WHEN '1' THEN 'High'
                      WHEN '200' THEN 'GOOD'
                      ELSE CAST(B.Type_ID AS CHAR(50)) END AS Type
FROM A
INNER JOIN B ON A.AID = B.AID;