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TypeScript中的object参数映射到另一个object有简写吗?

[英]Is there a shorthand for mapping object parameters to another object in TypeScript?

Example:例子:

response.rooms.push({
  maxPlayers: doc.maxPlayers,
  ownderId: doc.ownderId,
  roomId: doc.ownderId,
  state: doc.state,
  type: doc.type,
});

The parameters all have same name.参数都具有相同的名称。 The doc object also contains parameters that I don't want to map to rooms . doc object 还包含我不想 map 到rooms的参数。 Any ideas?有任何想法吗? Because this is a short one and it gets really annoying with larger objects.因为这是一个很短的对象,而且对于较大的对象来说真的很烦人。

If you are 100% sure that the properties always match, you can try this:如果您 100% 确定属性始终匹配,您可以试试这个:

response.rooms.push({...doc})

The doc object also contains parameters that I don't want to map to rooms.文档 object 还包含我不想 map 到房间的参数。

You'll have to explicitly declare what you want from doc at some point.您必须在某些时候明确声明您想要从doc获得什么。 For large objects adding a function, buildRoom , makes the desired shape still using dot access or destructuring in its implementation and may reduce tedium.对于大型对象,添加 function, buildRoom ,使所需的形状在其实现中仍然使用点访问或解构,并可能减少单调乏味。

function buildRoom1(obj: typeof doc) {
  const {
    maxPlayers,
    ownerId,
    state,
    type,
    ...
  } = doc;

  return {
    maxPlayers,
    ownerId,
    roomId: doc.ownerId,
    state,
    type
  }; 
}
response.rooms.push(buildRoom(doc));

Flamboyantly:华丽地:

function pluck<T extends Record<PropertyKey, any>, K extends keyof T>(obj: T, ...fields: K[]) {
    return fields.reduce((acc, field) => ({ ...acc, [field]: obj[field] }), {} as Pick<T, K>);
}
 
const room = pluck(doc, "ownderId", "state", "type", "maxPlayers");
response.rooms.push({ ...doc, roomId: room.ownderId });

then with more indirection:然后更间接:

function buildRoom2(obj: typeof doc) {
  const props = pluck(obj, "ownderId", "state", "type", "maxPlayers");
  return { ...props, roomId: props.ownderId };
}
response.rooms.push(buildRoom2(doc));

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