php 正则表达式匹配和替换 html a 标签排除域

Question

I found links and replace with nofollow. But I need if "<a(.*)" line contains "google.com" stop replace.

This is my code:

preg_replace('#(<a\s)#is', '\\1rel="nofollow noreferrer ugc" target="_blank" ', $post->content);

Inputs:

<a href="https://www.burtinet.com/">Hosting</a>
<a href="https://www.google.com/">Search</a>

Output:

<a rel="nofollow noreferrer ugc" target="_blank" href="https://www.burtinet.com/">Hosting</a>
<a rel="nofollow noreferrer ugc" target="_blank" href="https://www.google.com/">Search</a>

I need:

<a rel="nofollow noreferrer ugc" target="_blank" href="https://www.burtinet.com/">Hosting</a>
<a href="https://www.google.com/">Search</a>

Answer 1

try this it should do what you are looking for, I just updated your regular expression to ignore replacing if it contains google. we can enhance it a bit more and be specific to the href if you would like to.

$output  = preg_replace('#((?!.*google)(<a\s))#is', '\\1rel="nofollow noreferrer ugc" target="_blank" ', $post->content);