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根据 Pandas 中列满足的条件删除一组列

[英]Dropping a group of columns based on a condition fulfilled by a column in Pandas

I have a dataframe whereby the column names are tuples.我有一个 dataframe,列名是元组。 Below is a sample data for my dataframe:下面是我的 dataframe 的示例数据:

data = {"('7086', 'Open')": {5: 0.0700000002980232, 6: 0.0649999976158142, 7: 0.0750000029802322, 8: 0.0649999976158142, 9: 0.0700000002980232},
 "('7086', 'High')": {5: 0.0700000002980232, 6: 0.0750000029802322, 7: 0.0750000029802322, 8: 0.0750000029802322, 9: 0.0700000002980232},
 "('7086', 'Low')": {5: 0.0700000002980232, 6: 0.0649999976158142, 7: 0.0750000029802322, 8: 0.0649999976158142, 9: 0.0700000002980232},
 "('7086', 'Close')": {5: 0.0700000002980232, 6: 0.0750000029802322, 7: 0.0750000029802322, 8: 0.0750000029802322, 9: 0.0700000002980232},
 "('7086', 'Adj Close')": {5: 0.0700000002980232, 6: 0.0750000029802322, 7: 0.0750000029802322, 8: 0.0750000029802322, 9: 0.0700000002980232},
 "('7086', 'Volume')": {5: 0, 6: 3200, 7: 0, 8: 200800, 9: 260000},
 "('03028', 'Open')": {5: 0.3600000143051147, 6: 0.3600000143051147, 7: 0.3600000143051147, 8: 0.3600000143051147, 9: 0.3600000143051147},
 "('03028', 'High')": {5: 0.3600000143051147, 6: 0.3600000143051147, 7: 0.3600000143051147, 8: 0.3600000143051147, 9: 0.3600000143051147},
 "('03028', 'Low')": {5: 0.3600000143051147, 6: 0.3600000143051147, 7: 0.3600000143051147, 8: 0.3600000143051147, 9: 0.3600000143051147},
 "('03028', 'Close')": {5: 0.3600000143051147, 6: 0.3600000143051147, 7: 0.3600000143051147, 8: 0.3600000143051147, 9: 0.3600000143051147},
 "('03028', 'Adj Close')": {5: 0.3509772419929504, 6: 0.3509772419929504, 7: 0.3509772419929504, 8: 0.3509772419929504, 9: 0.3509772419929504},
 "('03028', 'Volume')": {5: 15500.0, 6: 0.0, 7: 0.0, 8: 0.0, 9: 0.0}}
df = pd.DataFrame(data)

   ('7086', 'Open')  ...  ('03028', 'Volume')
5             0.070  ...              15500.0
6             0.065  ...                  0.0
7             0.075  ...                  0.0
8             0.065  ...                  0.0
9             0.070  ...                  0.0

[5 rows x 12 columns]

Now, what I hope to perform is to remove the group of columns with the same number code when one of the columns in the number code has only 1 unique number:现在,我希望执行的是当数字代码中的其中一列只有 1 个唯一数字时,删除具有相同数字代码的一组列:

df.nunique()

('7086', 'Open')          3
('7086', 'High')          2
('7086', 'Low')           3
('7086', 'Close')         2
('7086', 'Adj Close')     2
('7086', 'Volume')        4
('03028', 'Open')         1
('03028', 'High')         1
('03028', 'Low')          1
('03028', 'Close')        1
('03028', 'Adj Close')    1
('03028', 'Volume')       2
dtype: int64

As above, we can see in the number code 03028 , that 5 out of 6 columns have only 1 unique value.如上,我们可以在数字代码03028中看到,6 列中的 5 列只有 1 个唯一值。 Therefore, I wish to remove all the 6 columns with the same number code based on this fact.因此,我希望根据这个事实删除所有具有相同数字代码的6列。 Is there any idea I can do that?有什么想法我可以做到吗? I was thinking of grouping it together and dropping it.我正在考虑将它组合在一起并删除它。 But I'm not sure how to deal with the tuples.但我不确定如何处理元组。 Thanks in advance.提前致谢。

My expected output will be:我预期的 output 将是:

   ('7086', 'Open')  ...  ('7086', 'Volume')
5             0.070  ...                   0
6             0.065  ...                3200
7             0.075  ...                   0
8             0.065  ...              200800
9             0.070  ...              260000

[5 rows x 6 columns]

You can do你可以做

out = df.loc[:,~df.columns.str.contains("'03028',")]

If multiple如果多个

out = df.loc[:,~df.columns.str.contains("'03028',|'00000',")]

Try something like this尝试这样的事情

import ast

df.columns = pd.MultiIndex.from_tuples(map(ast.literal_eval, df.columns))

filter_ = (df.nunique()==1).groupby(level=0).any()
df.drop(filter_[filter_].index, axis=1, level=0)

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