[英]SQLAlchemy Select from Join of two Subqueries
Need help translating this SQL query into SQLAlchemy:需要帮助将此 SQL 查询转换为 SQLAlchemy:
select
COALESCE(DATE_1,DATE_2) as DATE_COMPLETE,
QUESTIONS_CNT,
ANSWERS_CNT
from (
(select DATE as DATE_1,
count(distinct QUESTIONS) as QUESTIONS_CNT
from GUEST_USERS
where LOCATION like '%TEXAS%'
and DATE = '2021-08-08'
group by DATE
) temp1
full join
(select DATE as DATE_2,
count(distinct ANSWERS) as ANSWERS_CNT
from USERS
where LOCATION like '%TEXAS%'
and DATE = '2021-08-08'
group by DATE
) temp2
on temp1.DATE_1=temp2.DATE_2
)
Mainly struggling with the join of the two subqueries.主要是在努力连接两个子查询。 I've tried this (just for the join part of the SQL):我试过这个(只是为了 SQL 的连接部分):
query1 = db.session.query(
GUEST_USERS.DATE_WEEK_START.label("DATE_1"),
func.count(GUEST_USERS.QUESTIONS).label("QUESTIONS_CNT")
).filter(
GUEST_USERS.LOCATION.like("%TEXAS%"),
GUEST_USERS.DATE == "2021-08-08"
).group_by(GUEST_USERS.DATE)
query2 = db_session_stg.query(
USERS.DATE.label("DATE_2"),
func.count(USERS.ANSWERS).label("ANSWERS_CNT")
).filter(
USERS.LOCATION.like("%TEXAS%"),
USERS.DATE == "2021-08-08"
).group_by(USERS.DATE)
sq2 = query2.subquery()
query1_results = query1.join(
sq2,
sq2.c.DATE_2 == GUEST_USERS.DATE)
).all()
In this output I receive only the DATE_1 column and the QUESTIONS_CNT columns.在这个 output 中,我只收到 DATE_1 列和 QUESTIONS_CNT 列。 Any idea why the selected output from the subquery is not being returned in the result?知道为什么没有在结果中返回从子查询中选择的 output 吗?
Not sure if this is the best solution but this is how I got it to work.不确定这是否是最好的解决方案,但这就是我让它工作的方式。 Using 3 subqueries essentially.本质上使用 3 个子查询。
query1 = db.session.query(
GUEST_USERS.DATE_WEEK_START.label("DATE_1"),
func.count(GUEST_USERS.QUESTIONS).label("QUESTIONS_CNT")
).filter(
GUEST_USERS.LOCATION.like("%TEXAS%"),
GUEST_USERS.DATE == "2021-08-08"
).group_by(GUEST_USERS.DATE)
query2 = db_session_stg.query(
USERS.DATE.label("DATE_2"),
func.count(USERS.ANSWERS).label("ANSWERS_CNT")
).filter(
USERS.LOCATION.like("%TEXAS%"),
USERS.DATE == "2021-08-08"
).group_by(USERS.DATE)
sq1 = query1.subquery()
sq2 = query2.subquery()
query3 = db.session.query(sq1, sq2).join(
sq2,
sq2.c.DATE_2 == sq1.c.DATE_1)
sq3 = query3.subquery()
query4 = db.session.query(
func.coalesce(
sq3.c.DATE_1, sq3.c.DATE_2),
sq3.c.QUESTIONS_CNT,
sq3.c.ANSWERS_CNT
)
results = query4.all()
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