如何使 CGIHTTPRequestHandler 使用 POST 数据执行我的 PHP 脚本

Question

I am currently trying to do simple web stuff with the http.server module in Python. When I try to POST a form to my script, it does not receive the POST data, $_POST ist empty and file_get_contents('php://input') as well.我目前正在尝试使用 Python 中的http.server模块执行简单的 web 操作。当我尝试将表单发布到我的脚本时，它没有收到 POST 数据， $_POST _POST 是空的并且file_get_contents('php://input')也是如此。

This is my post_test.html :这是我的post_test.html ：

#!/usr/bin/php

<!DOCTYPE html>
<html>
<body>

<form method="post" action="post_test.html">
  Name: <input type="text" name="fname">
  <input type="submit">
</form>

<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
    // collect value of input field
    echo "RAW POST: " . file_get_contents('php://input') . "<br>";
    $name = $_POST['fname'];
    if (empty($name)) {
        echo "Name is empty";
    } else {
        echo $name;
    }
}
?>

</body>
</html>

And this is my server script:这是我的服务器脚本：

import urllib.parse
from http.server import CGIHTTPRequestHandler, HTTPServer

hostName = "localhost"
serverPort = 8080

handler = CGIHTTPRequestHandler
handler.cgi_directories.append('/php-cgi')


class MyServer(handler):

    def do_GET(self):
        # get path without first '/' and without anything besides path and filename
        file = self.path[1:].split("?")[0].split("#")[0]
        # if the file is in the script list, execute from php-cgi, else load from webapp
        php_handle = ["post_test.html"]
        if file in php_handle:
            self.path = "/php-cgi" + self.path
        else:
            self.path = "/webapp" + self.path
        CGIHTTPRequestHandler.do_GET(self)

    def do_POST(self):
        # get path without first '/' and without anything besides path and filename
        file = self.path[1:].split("?")[0].split("#")[0]
        # if the file is in the script list, execute from php-cgi
        php_handle = ["post_test.html"]
        if file in php_handle:
            length = int(self.headers['Content-Length'])
            post_data = urllib.parse.parse_qs(self.rfile.read(length).decode('utf-8'))
            for key, data in post_data.items():
                self.log_message(key + ": " + str.join(", ", data))

            self.path = "/php-cgi" + self.path
            CGIHTTPRequestHandler.do_POST(self)

    def do_HEAD(self):
        CGIHTTPRequestHandler.do_HEAD(self)


if __name__ == "__main__":
    webServer = HTTPServer((hostName, serverPort), MyServer)
    try:
        webServer.serve_forever()
    except KeyboardInterrupt:
        pass
    webServer.server_close()
    print("Server stopped.")

Answer 1

Okay, I was finally able to solve the problem: #!/usr/bin/php is wrong, it should be #!/usr/bin/php-cgi .好的，我终于能够解决问题了： #!/usr/bin/php是错误的，应该是#!/usr/bin/php-cgi 。

Reason : php does NOT use the POST data, and there is no way giving it to php. php-cgi is made for the webserver purpose and can handle it.原因： php不使用 POST 数据，无法将其提供给 php。php php-cgi是为网络服务器目的而制作的，可以处理它。

Hwo to solve the next problem : To run php-cgi successfully you have to create a php.ini in the current directory tho, with two settings. Hwo 解决下一个问题：要成功运行php-cgi ，您必须在当前目录中创建一个 php.ini，其中包含两个设置。 First one to allow executing it directly, second one to set the directory where the scripts are.第一个允许直接执行它，第二个设置脚本所在的目录。 If you don't set it, you will be greeted with a 404 not found .如果你不设置它，你会收到404 not found的问候。

php.ini : php.ini ：

cgi.force_redirect = 0
doc_root = /home/username/server-directory

Where the server-directory folder is the folder containing the php.ini, and the php-cgi folder.其中server-directory文件夹是包含 php.ini 和php-cgi文件夹的文件夹。 Also the name of the folder is not related to the php-cgi binary, it's just bad naming that I did.此外，该文件夹的名称与 php-cgi 二进制文件无关，这只是我所做的错误命名。

If you try to recreate this, it should work perfectly now.如果您尝试重新创建它，它现在应该可以完美运行。

如何使 CGIHTTPRequestHandler 使用 POST 数据执行我的 PHP 脚本

问题描述

1 个解决方案

解决方案1
1 已采纳 2022-04-11 19:46:14

如何使 CGIHTTPRequestHandler 使用 POST 数据执行我的 PHP 脚本

问题描述

1 个解决方案

解决方案1 1 已采纳 2022-04-11 19:46:14

解决方案1
1 已采纳 2022-04-11 19:46:14