在 Python 的键盘中按下特定字符/数字时如何按下按钮？

Question

i have a simple calculator program that is running in a window with Tkinter that i called window = Tk() , i have created normal buttons but i want that when i press for example "1" the bottun 1 is pressed, as if i clicked the button with the mouse. So how can i detect if the specific number 1 is pressed? Because for now the program prints "Hello" (it's for check that the character detection works) but with any letter/character i press, how to set a specific number for example "1"? Thanks a lot and try to be clear i'm a beginner

bottone1= Button(window,text= "1", font= ('Helvetica 20 '),width=6,height=1,bg="#008BC7", command=lambda:button_press(1))

def var (e):
    print("Hello")

window.bind("", var)

window.mainloop()

Answer 1

You can bind certain keys to a function that takes a *args param - in case of the button press with your mouse the parameter will be None - if you bind a key it will hold the keyevent:

from tkinter import *

def pressMeFunc(*args):
    if args:
        print(args[0].char)  # leverage the keyPressed event fields
    else:
        print("Hello")

window = Tk() 

b = Button(window, text="Press Me", command=pressMeFunc)
b.pack()

window.bind("1",  pressMeFunc)
window.bind("2",  pressMeFunc)
window.bind("3",  pressMeFunc)

window.mainloop()

If you start this and press the "2" key, you get in *args a KeyPress event:

You can use its .char field to get the key pressed.

---

You could create a dictionary with a "key" to "function" mapping and leverage that to call things depending on the key pressed:

def one(): 
    print("ONE")

def two(): 
    print ("TWO")

def default_thing(*_):
    print("Hello")

do_stuff_mapping = {"1": one, "2": two}

def pressMeFunc(*args):    
    if args:
        print(args[0].char)
        # get the function as defined above or default one 
        # if key is not mapped to a function - then call it 
        do_stuff_mapping.get(args[0].char, default_thing) ()
    else:
        default_thing(None)