[英]JS - how to replace in regex for links
I have a regex that replaces the link from the moment http to the occurrence of certain characters in []
, I would like to add
我有一个正则表达式替换了从 http 到[]
中某些字符出现的链接,我想添加
to these characters - that is to replace the string with the occurrence of certain characters or a hard space:到这些字符 - 即用某些字符或硬空格的出现替换字符串:
"https://test.pl'".replace(/https?:\/\/[^ "'><]+/g," ")
Works fine for the characters mentioned in []
, I don't know how to add here  
;对于[]
中提到的字符工作正常,我不知道如何在这里添加 
;
You can use您可以使用
.replace(/https?:\/\/.*?(?: |[ '"><]|$)/g," ")
See the regex demo .请参阅正则表达式演示。
Details :详情:
https?:\/\/
- http://
or https://
https?:\/\/
- http://
或https://
.*?
- any zero or more chars other than line break chars as few as possible - 尽可能少的换行字符以外的任何零个或多个字符(?: |[ '"><]|$)
- one of the following: (?: |[ '"><]|$)
- 以下之一:
-
-
char sequence字符序列|
- or - 或者[ "'><]
- a space, "
, '
, >
or <
char [ "'><]
- 空格、 "
、 '
、 >
或<
字符|
- or - 或者$
- end of string. $
- 字符串结尾。JavaScript demo: JavaScript 演示:
const texts = ["https://test.pl test","https://test.pl'test"]; const re = /https?:\/\/.*?(?: |[ '"><]|$)/g; for (const s of texts) { console.log(s, '=>', s.replace(re, " ")); }
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