[英]How to apply function to each row of dataframe in R?
I want to apply given function to each row of dataframe and use another values of row, as input parameters/arguments:我想将给定的 function 应用于 dataframe 的每一行,并使用行的另一个值作为输入参数/参数:
Model <- c("H5", "H5", "H5","H4")
Length <- c(6, 6, 6, 6)
Code <- c("030299", "010121","030448","030324")
df <- data.frame(Model,Length,Code)
Model Length Code
HS5 6 030299
HS5 6 010121
HS5 6 030448
HS4 6 030324
I want to apply the following code to each row and generate the outcome as a new column我想将以下代码应用于每一行并将结果生成为新列
Library(concordance)
concord(sourcevar = (each row of 'Code' column), origin = as.character(character in 'Model' column) , destination = "HS4", dest.digit = as.numeric(number in 'Length' column), all = F))
Documentation Page 6 文档第 6 页
You can use apply
on the rows ( MARGIN = 1
).您可以在行上使用apply
( MARGIN = 1
)。
apply(df, MARGIN = 1, function(x) concord(sourcevar = x[3], origin = x[1], destination = "HS4", dest.digit = x[2], all = F))
However, this does not work because there is no conversion dictionary between "HS4" and "HS4", so you can use apply
only on the rows that are not HS4:但是,这不起作用,因为“HS4”和“HS4”之间没有转换字典,因此您只能在非 HS4 的行上使用apply
:
df$New <- df$Code
df[df$Model != "HS4", ]$New <- apply(df[df$Model != "HS4", ], 1, \(x) concord(sourcevar = x[colnames(df) == "Code"],
origin = x[colnames(df) == "Model"], destination = "HS4",
dest.digit = x[colnames(df) == "Length"], all = F))
Model Length Code New
1 HS5 6 030299 030289
2 HS5 6 010121 010121
3 HS5 6 030448 030449
4 HS4 6 030324 030324
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