如何索引字符串数组

Question

I have a string array in C# 3.5:

string [] times = new[] {“08:00 am” , “10:00 am”, “120”} ; 

I would like to create indexes to times: StartTime , EndTime , ElapsedTime so that when I code:

StartTime= “09:00 am” ; 
EndTime= “11:00 am” ; 

then times[0] is set to “09:00 am” , etc.

I could create 3 methods:

private void StartTime(string time)
{    times[0] = time;  }
private void EndTime(string time)
{    times[1] = time;  }
private void ElapsedTime(string time)
{    times[2] = time;   }

and code

StartTime("09:00");  

but is there a simpler way to do it?

Answer 1

What you should really do is create a new class to do this. Make the two times properties.

And the time elapsed is a function of the start and end times.

class Time 
{
    public DateTime StartTime{ get; set; }
    public DateTime EndTime{ get; set; }

    public String[] ToStringArray() 
    {
        String[] ret = new String[3];
        ret[0] = StartTime.ToString();
        ret[1] = EndTime.ToString();
        ret[2] = ElapsedTime().ToString();
        return ret;
    }

    public TimeSpan ElapsedTime() 
    {
        return EndTime.subtract(StartTime);
    }
}

Answer 2

I don't know it it is simpler, but I would suggest taking the hard index references out of your code and replace them with constants, to make easier to maintain if the order of elements in the array would change in the future:

private const int START_TIME = 0;
private const int END_TIME = 1;
private const int ELAPSED_TIME = 2;

Then you will also get more readable code:

times[END_TIME] = time;

Unless you want to be more object oriented, in which case you should follow jjnguy's advice.

Answer 3

要添加到jjnguy的答案中，您确实应该有一个包含3个属性的类，然后，如果需要一个数组，则可以有一个公共属性，该属性只有一个getter并在字符串数组中返回3个不同的时间。

Answer 4

Use a dictionary. See here .

Answer 5

How about an extension method?

public static class Extensions
{
   public static void StartTime(this string[] array, string value)
   {
      array[0] = value;
   }
}

Answer 6

You can do this using a dictionary.

eg

Dictionary<string, string> times = new Dictionary<string, string>();
times.Add("StartTime","09:00am");
times.Add("EndTime","11:00am");