[英]Join on two columns, if null then only join on one
I have the following two tables:我有以下两个表:
customers:顾客:
customer_id客户ID | department_id部门编号 |
---|---|
aaaa啊啊啊 | 1234 1234 |
bbbb bbbb | 3456 3456 |
status:地位:
department_id部门编号 | customer_id客户ID | status地位 |
---|---|---|
1234 1234 | NULL NULL | silver银 |
3456 3456 | bbbb bbbb | gold金子 |
1234 1234 | bbbb bbbb | gold金子 |
I want to join status on customers, but if if it returns NULL I want to give the customer the department default.我想加入客户状态,但如果它返回 NULL 我想给客户部门默认值。 My ideal Output for this would be the following:我理想的 Output 如下:
customer_id客户ID | department_id部门编号 | status地位 |
---|---|---|
aaaa啊啊啊 | 1234 1234 | silver银 |
bbbb bbbb | 3456 3456 | gold金子 |
I have tried to do two left joins, but am getting a memory usage error.我尝试执行两个左连接,但出现 memory 使用错误。 Is there another way to do this that is efficient?还有另一种有效的方法吗?
You can do:你可以做:
select c.*, coalesce(s.status, d.status) as status
from customers c
left join status d on d.department_id = c.department_id
and d.customer_id is null
left join status s on s.department_id = c.department_id
and s.customer_id = c.customer_id
This might work:这可能有效:
SELECT *,
(
SELECT TOP 1 status
FROM status s
WHERE s.customer_id = c.customer_id
OR (c.customer_id IS NULL AND s.department_id = c.department_id)
ORDER BY CASE WHEN s.customer_id is NOT NULL THEN 0 ELSE 1 END
) as status
FROM customers c
The kicker is what kind of database you're using.问题在于您使用的是哪种数据库。 If it's MySql you might want LIMIT 1 instead of TOP 1. For Oracle you'd look at the ROWNUM field.如果它是 MySql,您可能需要 LIMIT 1 而不是 TOP 1。对于 Oracle,您需要查看 ROWNUM 字段。
Assuming that there is always a match at least on the department_id
, you need an INNER
join and FIRST_VALUE()
window function will pick the proper status
:假设至少在department_id
上总有一个匹配项,您需要一个INNER
连接并且FIRST_VALUE()
window function 将选择正确的status
:
SELECT DISTINCT
c.customer_id,
c.department_id,
FIRST_VALUE(s.status) OVER (
PARTITION BY c.customer_id, c.department_id
ORDER BY CASE
WHEN s.customer_id = c.customer_id THEN 1
WHEN s.customer_id IS NULL THEN 2
ELSE 3
END
) status
FROM customers c INNER JOIN status s
ON s.department_id = c.department_id;
Depending on the database that you use the code may be simplified.根据您使用的数据库,代码可能会被简化。
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