Qmap中的Qtimer对象发送的超时信号是从哪个key发出来的？

Question

In a function, how to understand the signal sent from Qtimer objects that I created in Qmap, how to find from which object the signal comes from in the slot function.

I created Qmap above code SQL.h

public slots:
 void experiment();
 void run();
private:
 QMap<QString,QTimer*> job;

I create QMap value and key with Qtimer. SQL.cpp

void SQL::experiment()
{
  QTimer *timer=new Qtimer();
   
  job.insert("dd",timer);

  QTimer *timer1=new Qtimer();
  job.insert("ss",timer1);
 
  job.value("dd")->start();
  job.value("dd")->setInterval)(5000);


  job.value("ss")->start();
  job.value("ss")->setInterval)(10000);

  connect(job.value("dd"),SIGNAL(timeout()),this,SLOT(run()));
  connect(job.value("ss"),SIGNAL(timeout()),this,SLOT(run()));

}

In this slot, how can I understand which of the Qtimer in the Qmap receives a signal at that time?

void SQL::run()
{
  //job.value(key)  // how to understand key

}

I thought I could use sender() with Qmapiterator, but I couldn't find out how. can you help?

Answer 1

Old way is using QSignalMapper . You could also set the key as dynamic property of the timer object, so you could access it through QObject::sender() . But, today you should probably just use a lambda.

First, change the run slot to take any parameters you want:

void SQL::run(const QString &key)
{
    QTimer *timer = job.value(key);
}

Then, just use lambda to easily pass the required parameters

QString name="ff";
connect(job.value(name), &QTimer::timeout, this, [this, name]() { 
            run(name); 
        });
        // name is capture by value above,
        // so changing name variable later does not
        // affect the value captured by the lambda

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As a side note, you shouldn't use the old SIGNAL() and SLOT() macros unless you really have to for some reason. Use the "new" (10 years old) connect syntax.