[英]How to get only key value pairs in nested object in javascript
let Ar=[
{
info:{
name:"Sai",
age:24
},
grade:'A'
},
{
name:"Satish",
grade:'B',
info:{
place:"Hyd",
company:'Company1'
},
info2:{
place2:"Hyderabad",
company2:'Company2'
}
}
] ]
**Output should be key values pairs only ** **输出应该只是键值对**
[
{
"name": "Sai",
"age": 24,
"grade": "A"
},
{
"name": "Satish",
"grade": "B",
"place": "Hyd",
"company": "Company1",
"place2": "Hyderabad",
"company2": "Company2"
}
]
How we can get only key value pairs form the object and nested object
*Current solution I have like this But do we have more optimized code to get the only key value pairs from an object. I have used Object.keys(obj) and Object.entries(obj) methods to achieve * *我目前的解决方案是这样的但是我们是否有更优化的代码来从 object 中获取唯一的键值对。我使用了 Object.keys(obj) 和 Object.entries(obj) 方法来实现 *
let fr=Ar.map((A)=>{
let test=[];
let en= Object.keys(A).map((item) => {
if (typeof A[item] === "object") {
Object.entries(A[item]).map((i)=>{test.push(i)})
} else {
return test.push([item, A[item]]);
}
});
return test;
})
let finalAnswer=fr.map((item)=>{
return Object.fromEntries(item)
})
console.log("Spread Print",finalAnswer)
Is there any better solution than me?有没有比我更好的解决方案?
You can use this你可以用这个
let fr=Ar.map((A)=>{
let test={};
Object.keys(A).forEach((item) => {
if (typeof A[item] === "object") {
test={...test,...A[item]};
} else {
test[item]=A[item]
}
} return test });
} return test });
The below may be one possible solution (using recursion) to achieve the desired objective.以下可能是实现预期目标的一种可能解决方案(使用递归)。
Please note that if there are duplicate keys in nested levels, only the latest/last key-value pair will be retained.请注意,如果嵌套级别中存在重复的键,则只会保留最新/最后的键值对。
Code Snippet代码片段
// recursive method to transform nested objects const recTxf = parm => { if (Array.isArray(parm)) { // if key-value pair array const [k, v] = parm; // either recurse to nested, or return key-value pair if (typeof v === 'object') return recTxf(v); else return { [k]: v }; } else return { // otherwise, it is object...Object.entries(parm) // iterate over key-value pairs.reduce( (acc, itm) => ({ // use "reduce" to accumulate/aggregate...acc, ...recTxf(itm) // aggregate results of the recursive calls }), {} ) }; }; // method to iterate over the array const myTransform = arr => arr.map(ob => recTxf(ob)); let Ar = [ { info: { name: "Sai", age: 24 }, grade: 'A' }, { name: "Satish", grade: 'B', info: { place: "Hyd", company: 'Company1' }, info2: { place2: "Hyderabad", company2: 'Company2' } } ]; console.log(myTransform(Ar));
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Explanation解释
Inline comments are provided in the snippet above.上面的代码片段中提供了内嵌注释。
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