如何转义用作列名的保留字？ 谷歌数据工作室

Question

I am using Google data studio to produce some data dashboards, as part of this I am creating a calculated field on the dataset that strips the numeric value from an alphanumeric string ie 7 out of 7A.

I'm then using a case statement to assign another number to the striped value ie where the formula returns 7 the case statement assigns this to 1000, 8 as 2000, 9 to 3000 ect

The problem I am having is that in the dataset three of the fields are titled 7, 8 and 9. As such in the below formula the first three lines are comparing the striped field to the fields titled 7, 8 or 9 and not to the numeric value of 7, 8 or 9

I need to be able to escape the 7,8 or 9 characters in the formula so they are treated as a numeric value and not a referance to a field in the dataset.

case
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 7 then 1000
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 8 then 2000
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 9 then 3000
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 10 then 4000
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 11 then 5000
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 12 then 6000
    when CAST(REGEXP_REPLACE(YearGroup, R"\D+", "") AS NUMBER)= 13 then 7000
end

Answer 1

To strip a part of a string, please use REGEXP_EXTRACT .

First check for a number, the text may only contain digits. If it is a number convert the text field to a number.

If the text field contains digits ( \d+ ) followed by a none digit ( \D ), the extract the digits. Convert it to a number and do your calculation.

CASE
  WHEN REGEXP_MATCH(YearGroup, r"\d+") THEN CAST(YearGroup AS number )
  WHEN CAST(REGEXP_EXTRACT(YearGroup, r"(\d+)\D") AS number ) BETWEEN 7 AND 13 THEN 
    1000 * ( CAST(REGEXP_EXTRACT(YearGroup, r"(\d+)\w") AS number ) - 6 )
  ELSE NULL
END