如何从对象数组中检索 object 并使用 javascript 检索 arrays

Question

I have array of objects and arrays.

If the array of objects has value property same

• and if place includes of arrraylist list return first obj

• and if place is equal includes/not includes return first obj

if no above conditions return undefined; using javascript

var list=['SG','TH','MY']


var arrobj1=[
  {id:1, name:'userone',place:'SG', value:100},
  {id:2, name:'usertwo',place:'TH', value:100},
  {id:3, name:'userthree',place:'IL',value:200},
]
Expected Output
{id:1, name:'userone',place:'SG', value:100}

****
var arrobj2=[
  {id:1, name:'userone',place:'IN', value: 200},
  {id:2, name:'usertwo',place:'SL',value: 100},
  {id:3, name:'userthree',place:'SL', value: 100},
]
Expected Output
{id:2, name:'usertwo',place:'SL',value: 100}
****
var arrobj3=[
  {id:1, name:'userone',place:'SL', value:10},
  {id:2, name:'usertwo',place:'IN', value:20},
  {id:3, name:'userthree',place:'KL', value:30},
]
Expected Output
undefined

Tried

var result= arrobj.find(e=>{
  if((e.value === e.value) && (list.includes(e.place)){
   return e
  }
})

Answer 1

I've added inline comments to correspond to the requirements. I wasn't sure exactly what you meant in some cases, so I can adjust the answer if you clarify the question

 var list = ['SG', 'TH', 'MY'] var arrobj1 = [{ id: 1, name: 'userone', place: 'SG', value: 100 }, { id: 2, name: 'usertwo', place: 'TH', value: 100 }, { id: 3, name: 'userthree', place: 'IL', value: 200 }, ] //Expected Output //{id:1, name:'userone',place:'SG', value:100} //**** var arrobj2 = [{ id: 1, name: 'userone', place: 'IN', value: 200 }, { id: 2, name: 'usertwo', place: 'SL', value: 100 }, { id: 3, name: 'userthree', place: 'SL', value: 100 }, ] //Expected Output //{id:2, name:'usertwo',place:'SL',value: 100} //**** var arrobj3 = [{ id: 1, name: 'userone', place: 'SL', value: 10 }, { id: 2, name: 'usertwo', place: 'IN', value: 20 }, { id: 3, name: 'userthree', place: 'KL', value: 30 }, ] //Expected Output //undefined function getMatch(places, arrObj) { //.find will return the first item that matches the condition provided return arrObj.find( l => list.includes(l.place) // either the place of this item must exist in the list || arrObj.filter(arr => arr.value === l.value).length > 1) // or the value of this item must appear more than once in the list } console.log(getMatch(list, arrobj1)); console.log(getMatch(list, arrobj2)); console.log(getMatch(list, arrobj3));