获取字典列表的所有值

Question

I have list of dictionaries like this:

count = [{'A': 0}, {'B': 2}, {'C': 4}]

I want convert count to something like this:

count = [0, 2, 4]

Answer 1

You can do that with list comprehension:

count = [{'A': 0}, {'B': 2}, {'C': 4}]
[j for i in count for j in i.values()]

Output:

[0, 2, 4]

Answer 2

You can extract the values from each dictionary using a comprehension, and then you can use itertools.chain() to extract the values from each dictionary into one long iterator. This gives us a chain object, which we need to turn into a list using list() .

from itertools import chain

list(chain.from_iterable(item.values() for item in count))

This outputs:

[0, 2, 4]