如何在偶数和奇数的两个列表中将数字与可迭代对象分开？

Question

The function is supposed to take a list of numbers, and then generate two new lists separating even and uneven numbers in each one.

def separate(list):
    evenList = []
    unevenList = []
    for e in list:
        if e % 2 == 0:
            evenList.append(e)
        elif e % 1 == 0:
            unevenList.append(e)

    print(f"The even list is ", evenList)
    print(f"The uneven list is ", unevenList)        

I notice when my argument ends in an even number, it appends everything into the even list, and same if it ends in an uneven number with the uneven list. I just need a way to iterate based on the conditional, and append only those number that meet the criteria to each new list.

Answer 1

You can do it with two list comprehensions (also, you shouldn't overwrite the builtin python list ):

even_lst = [i for i in lst if not i % 2]
odd_lst = [i for i in lst if i % 2]