编译器如何不将名为 size 的局部变量与 function 调用 size() 混淆？

Question

While reading a C++ textbook, I came across this specific piece of code:

vector<double> homework;
typedef vector<double>::size_type vec_sz;
vec_sz size = homework.size();

I wonder how isn't there any conflict during compilation since the local variable size and the function being called size() share the same name and (here expecting a correction if I am wrong) they are apparently in the same scope. If they aren't in the same scope, then how does the compiler handle these two names in a single statement?

Thanks for your time in advance I hope my question makes sense!

Answer 1

how isn't there any conflict during compilation since the local variable size

Because size in homework.size() is a qualified name . While the name size without any qualification is an unqualified name . When you wrote homework.size() only the class scope corresponding to the class name homework is searched. So there is no clash between the two names if you were to write:

//----vvvv-------------------->local variable named size
      size = homework.size();
//--------------------^^^^---->data member named size in class scope