如何从 bash 自动完成中删除单个命令

Question

How do I remove a single "command" from Bash's auto complete command suggestions? I'm asking about the very first argument, the command, in auto complete, not asking " How to disable bash autocomplete for the arguments of a specific command "

For example, if I have the command ls and the system path also finds ls_not_the_one_I_want_ever , and I type ls and then press tab, I want a way to have removed ls_not_the_one_I_want_ever from every being a viable option.

I think this might be related to the compgen -c list, as this seems to be the list of commands available.

---

Background: WSL on Windows is putting all the .dll files on my path, in addition to the .exe files that should be there, and so I have many dlls I would like to remove in my bash environment, but I'm unsure how to proceed.

Answer 1

Bash 5.0's complete command added a new -I option for this.

According to man bash —

• complete -pr [-DEI] [ name ...]

  [...] The -I option indicates that other supplied options and actions should apply to completion on the initial non-assignment word on the line, or after a command delimiter such as ; or | , which is usually command name completion . [...]

---

Example:

function _comp_commands()
{
    local cur=$2

    if [[ $cur == ls* ]]; then
        COMPREPLY=( $(compgen -c "$cur" | grep -v ls_not_wanted) )
    fi
}

complete -o bashdefault -I -F _comp_commands

Answer 2

Using @pynexj's answer, I came up with the following example that seems to work well enough:

if [ "${BASH_VERSINFO[0]}" -ge "5" ]; then
  function _custom_initial_word_complete()
  {
    if [ "${2-}" != "" ]; then
      if [ "${2::2}" == "ls" ]; then
        COMPREPLY=($(compgen -c "${2}" | \grep -v ls_not_the_one_I_want_ever))
      else
        COMPREPLY=($(compgen -c "${2}"))
      fi
    fi
  }

  complete -I -F _custom_initial_word_complete
fi