如何导入菜单按钮并在触发时运行 function？ (PyQt5)

Question

I have imported a menu bar button from "Design.ui" and tried to assign functions to it but it seems like there is an error.

Imported design.ui --> uic.loadUi("Design.ui", self)

Then importing the menu button from design.ui self.openFileButton = self.findChild(QStatusBar, "actionOpen")

(Error: 'NoneType' object has no attribute 'triggered' ) Then trying to assign functions in it and getting the error, self.openFileButton.triggered.connect(self.openImage)

Thanks for helping:)

Answer 1

After calling uic.loadUi() , you should be able to to directly use the QWidgets you created in the .ui file instead of calling self.findChild()

For example:

class MainWidget(QWidget):

   def __init__(self):
      QWidget.__init__(self)   
      uic.loadUi("Design.ui", self)
      self.openFileButton.triggered.connect(self.openImage)

   def openImage(self):
      # Does some code

Alternatively, you can set the loaded UI as a variable and use the widgets from there.

For Example:

class MainWidget(QWidget):

   def __init__(self):
      QWidget.__init__(self)   
      self.ui = uic.loadUi("Design.ui", self)
      self.ui.openFileButton.triggered.connect(self.openImage)

   def openImage(self):
      # Does some code