[英]Append New Slides from Sheets Data in Google Apps Script
I have set up a Google Apps Script to generate new templated slides from data contained in a spreadsheet .我已经设置了一个 Google Apps 脚本来根据电子表格中包含的数据生成新的模板化幻灯片。 This data would be updated regularly.
该数据将定期更新。 I plan to set a project trigger to generate new slides on a regular basis.
我计划设置一个项目触发器以定期生成新幻灯片。
Right now, I avoid the problem of duplicating slides during triggered updates by simply removing previously generated slides (see code example below) but I would love to simply append new slides rather than deleting and regenerating (to preserve any edits to previously generated slides).现在,我通过简单地删除以前生成的幻灯片(参见下面的代码示例)来避免在触发更新期间复制幻灯片的问题,但我更愿意简单地 append 新幻灯片而不是删除和重新生成(以保留对以前生成的幻灯片的任何编辑)。
Any tips and tricks from more experienced Javascript developers for this wayward R coder on how to approach this problem?对于这个任性的 R 编码器,更有经验的 Javascript 开发人员有没有关于如何解决这个问题的提示和技巧?
function myFunction() {
var dataSpreadsheetUrl = "https://docs.google.com/spreadsheets/d/1RjA4BJ4IKyjlh_l6vNaC7Q8wgUet1eNBo4_KJiF1pbQ/edit";
var ss = SpreadsheetApp.openByUrl(dataSpreadsheetUrl);
var deck = SlidesApp.getActivePresentation();
var sheet = ss.getSheetByName('test');
var values = sheet.getRange(2, 1, sheet.getLastRow(), sheet.getLastColumn()).getValues();
var slides = deck.getSlides();
var templateSlide = slides[1];
var presLength = slides.length;
// remove previously generated slides
// TODO: figure out how to append rather than delete and regenerate
for (var i = 2; i < slides.length; i++){
slides[i].remove()
}
values.forEach(function(page){
if(page[0]){
templateSlide.duplicate();
slides = deck.getSlides();
newSlide = slides[2];
var shapes = (newSlide.getShapes());
shapes.forEach(function(shape){
shape.getText().replaceAllText('{{name}}',page[0]);
shape.getText().replaceAllText('{{value1}}',page[1]);
shape.getText().replaceAllText('{{value2}}',page[2]);
shape.getText().replaceAllText('{{value3}}',page[3]);
shape.getText().replaceAllText('{{value4}}',page[4]);
shape.getText().replaceAllText('{{value5}}',page[5]);
shape.getText().replaceAllText('{{value6}}',page[6]);
shape.getText().replaceAllText('{{value7}}',page[7]);
shape.getText().replaceAllText('{{value8}}',page[8]);
shape.getText().replaceAllText('{{value9}}',page[9]);
shape.getText().replaceAllText('{{value10}}',page[10]);
});
presLength = slides.length;
newSlide.move(presLength);
}
});
}
Figured it out by updating the starting row by checking against presentation length!通过检查演示文稿长度来更新起始行来解决这个问题!
function myFunction() {
var dataSpreadsheetUrl = "https://docs.google.com/spreadsheets/d/1RjA4BJ4IKyjlh_l6vNaC7Q8wgUet1eNBo4_KJiF1pbQ/edit";
var ss = SpreadsheetApp.openByUrl(dataSpreadsheetUrl);
var deck = SlidesApp.getActivePresentation();
var sheet = ss.getSheetByName('test');
var slides = deck.getSlides();
var templateSlide = slides[1];
var presLength = slides.length;
// new data update //
var rowLength = sheet.getLastRow();
var startRow = 2;
// update startRow when not initial run
if(presLength != 2){
startRow = presLength;
}
// save newly generated data range
var values = sheet.getRange(startRow, 1, sheet.getLastRow(), sheet.getLastColumn()).getValues();
values.forEach(function(page){
if(page[0]){
templateSlide.duplicate();
slides = deck.getSlides();
newSlide = slides[2];
var shapes = (newSlide.getShapes());
shapes.forEach(function(shape){
shape.getText().replaceAllText('{{name}}',page[0]);
shape.getText().replaceAllText('{{value1}}',page[1]);
shape.getText().replaceAllText('{{value2}}',page[2]);
shape.getText().replaceAllText('{{value3}}',page[3]);
shape.getText().replaceAllText('{{value4}}',page[4]);
shape.getText().replaceAllText('{{value5}}',page[5]);
shape.getText().replaceAllText('{{value6}}',page[6]);
shape.getText().replaceAllText('{{value7}}',page[7]);
shape.getText().replaceAllText('{{value8}}',page[8]);
shape.getText().replaceAllText('{{value9}}',page[9]);
shape.getText().replaceAllText('{{value10}}',page[10]);
});
presLength = slides.length;
newSlide.move(presLength);
}
});
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.