Python python中如何将带特殊字符的字符串转成dict

Question

I'm trying to covert a string into a valid dict.

For example the string:

'{"value1":"\^stack\.\*/overflo\\w\$arr=1", "value2":"path c:\nord\tem\orme\test.exe"}'

I want to get a dict

{"value1":"\^stack\.\*/overflo\\w\$arr=1", 
 "value2":"path c:\nord\tem\norme\test.exe"} 

How to convert this string into a dict without loosing spicial characters and without using backslash escape.

a_string = '{"value1":"\^stack\.\*/overflo\\w\$arr=1", "value2":"path c:\nord\tem\orme\test.exe"}'
a_dict = json.loads(a_string) # desired result a_dict = {"value1":"^stack.*/overflo\w$arr=1", "value2":"path c:\nord\tem\orme\test.exe"}

Answer 1

first of all, regular expression ("regex" for short) is not contextual grammar, thus it cannot differentiate whether an asterix ("*") inside pair of braces needs to be preserved, while others must be removed. Regex treats every character equally.

If the extra characters (here: asterixes) appear only at the beginning and at the end of json-like string, and you know that there are two of them on both ends, you can use slices to achieve your goal:

a_string = '**{"key1":"value1","key2":"value2"}**'
json_string = a_string[2:len(a_string)-2] # shortly: a_string[2:-2]
d = json.loads(json_string)
print(d)
#>>> {"key1":"value1","key2":"value2"}

Answer 2

You could use a generator, something like this:

original_String = "John - 10 , Rick - 20, Sam - 30" 

result = dict((a.strip(), int(b.strip()))  
                     for a, b in (element.split('-')  
                                  for element in original_String.split(', ')))  

The original string is John - 10, Rick - 20, Sam - 30

The resultant dictionary is: {'John': 10, 'Rick': 20, 'Sam': 30}

Answer 3

if you can remove ** of the first and end of the string you can use this standard python package to transform any string that is like a dictionary into a valid dictionary.

>>> import ast
>>> a_string = r'{"value1":"\^stack\.\*/overflo\\w\$arr=1", "value2":"path c:\nord\tem\orme\test.exe"}'
>>> a_dict = ast.literal_eval(a_string)
>>> a_dict
{'value1': '\\^stack\\.\\*/overflo\\w\\$arr=1', 'value2': 'path c:\nord\tem\\orme\test.exe'}

python document: https://docs.python.org/3/library/ast.html#ast.literal_eval