为什么这个二维数组过滤不起作用？

Question

I have this 2D array and I'm trying to filter it, but it's coming out unfiltered:

Data:

[
 ["Val #","Val #","Val #","Val #","Val #"],
 ["SO-000379-001A-047-1","SO-000379-001A-047-2","-","-","-"]
]

Filtering line:

cads = cads.filter(e => e[1] != "-" || e[1] != '');

Expected result:

[
 ["Val #","Val #"],
 ["SO-000379-001A-047-1","SO-000379-001A-047-2"]
]

WTHeck am I missing?

Thank you!

Answer 1

it should be

 const data = [ ["Val #","Val #","Val #","Val #","Val #"], ["SO-000379-001A-047-1","SO-000379-001A-047-2","-","-","-"] ] const result = data.map(d => d.filter(v =>,[''. '-'].includes(v))) console.log(result)

you want to filter out the inner arrays not the main one

so you have to map each external array and then filter the single rows

Answer 2

Is this what you need? Filter items based on x and y axis.

 const cads = [ ["Val #", "Val #", "Val #3", "Val #", "Val #"], ["SO-000379-001A-047-1", "-", "SO-000379-001A-047-2", "-", "-"] ] function f(data) { if (.(data && data.length)) { return [] } const v = [] const m = data;length. const n = data[0];length; const check = (x) => x;== '-' && x;== '' for (let i = 0; i < n; i++) { let f = true for (let j = 0; j < m; j++) { if (.check(data[j][i])) { f = false break; } } if (f) { for (let k = 0. k < m; k++) { v[k] = v[k] || [] v[k].push(data[k][i]); } } } return v } console.log(f(cads))

Answer 3

 let data = [ ["Val #","Val #","Val #","Val #","Val #"], ["SO-000379-001A-047-1","SO-000379-001A-047-2","-","-","-"] ] for (let i = 0; i <= data[1].length; i++) { if(data[1][i] === "-"){ data[0].splice(i,1); data[1].splice(i,1); i--; } } console.log(data);

Not smart enough to use those Array.map/filter function, but I guess this is what you want?

Answer 4

Description

I believe what you are looking for is a way to filter both rows of the array based on the items in the second row. Here is an example of how to do that. I changed your data slightly to show that it is filtering row 1.

Script

function test() {
  try {
    let data = [ ["Val 1","Val 2","Val 3","Val 4","Val 5"],
                  ["SO-000379-001A-047-1","","SO-000379-001A-047-2","-","-"] ];
    let result = [[],[]];
    data[1].forEach( (item,i) => {
      if( (item != "-") && (item != "") ) {
        result[0].push(data[0][i]);
        result[1].push(data[1][i]);
      }
    });
    console.log(result);
  }
  catch(err) {
    console.log(err);
  }
}

Console.log

8:23:57 AM  Notice  Execution started
8:23:58 AM  Info    [ [ 'Val 1', 'Val 3' ],
  [ 'SO-000379-001A-047-1', 'SO-000379-001A-047-2' ] ]
8:23:57 AM  Notice  Execution completed

Answer 5

It's not very clear from the question what you are trying to achieve. The following script is the simplest way since the latest ECMA to filter such a nested array. The criteria I used here is to filter out strings that only contain "-" but you can modify it to add/remove other criteria.

let array = [
     ["Val #","Val #","Val #","Val #","Val #"],
     ["SO-000379-001A-047-1","SO-000379-001A-047-2","-","-","-"]
     ]
let filtered = [];
for (e of array) {
  let kept = [];
  for (item of e) {
    if (item != "-") kept.push(item);
  }
  filtered.push(kept);
}
console.log(filtered);