如何通过单击 url 打开我的 flutter 应用程序
[英]How to open my flutter app by clicking a url
问题描述
I'm working on a flutter app, and now I need to be able to open my app whenever a URL with a certain pattern is clicked.
我正在开发一个 flutter 应用程序，现在我需要能够在单击具有特定模式的 URL 时打开我的应用程序。
In other words, I'd like to have that option from a clicked URL saying "Which app do you want to use to open this link"换句话说，我想从点击的 URL 中获得该选项，说“您想使用哪个应用程序打开此链接”
and from the shown apps to open this link I want mine to be in there从显示的应用程序打开这个链接，我希望我的应用程序在那里
Is it possible?是否可以？ How can I do this?我怎样才能做到这一点？
Also, I need to say I have done this from Android Studio - Java, but never in flutter/dart, I am a newbie around flutter另外，我需要说我已经从 Android Studio - Java 完成了这个，但从来没有在 flutter/dart 中，我是 flutter 附近的新手
1 个解决方案
解决方案1
1 已采纳 2022-05-07 10:23:43
I have found the solution, this link is going to give you everything you need for deep linking in flutter:我找到了解决方案，此链接将为您提供在 flutter 中进行深度链接所需的一切：
https://pub.dev/packages/uni_links https://pub.dev/packages/uni_links
Documentation/Installation文档/安装
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.