为什么我会收到以下错误？ ValueError：以 10 为底的 int() 的无效文字：''

Question

Here is the code

from time import sleep
import keyboard

# Condição de partida da máquina
while True:
    if keyboard.is_pressed('ENTER'):
        print('\nProcessando...\n')
        sleep(2)
        break

print('\nRETIRE O CARTÃO.')

opcao = int(input('SELECIONE UMA OPÇÃO:\n'
                  '\033[32m[1] DEPÓSITO\033[m\n'
                  '\033[32m[2] SAQUE\033[m\n'
                  '\033[32m[3] SALDO/EXTRATO\033[m\n'
                  '\033[32m[4] POUPANÇA\033[m\n'))

and now, the error:

Traceback (most recent call last):
  File "-", line 18, in <module>
    opcao = int(input('SELECIONE UMA OPÇÃO:\n'
ValueError: invalid literal for int() with base 10: ''

I can't find what's wrong with the code... Someone can help me? I've already tried to rewrite the code, but this problem is really killing me...

Answer 1

Probably as input you entered string value which can't be casted to int type(in your case empty string - you pressed Enter ), it only accepts number like 1,2,10,15,-1, etc...

Answer 2

Solved, i've only changed the arg:

keyboard.is_pressed

to

keyboard.read_key