[英]Can someone point out the problem in my linked list implementation?
When I compile the following code, I get compile error that " head does not name a type".当我编译下面的代码时,出现“head does not name a type”的编译错误。 Can someone explain what goes wrong?有人可以解释出什么问题了吗?
#include <iostream>
using namespace std;
/* Link list node */
struct node {
int val;
struct node* next;
node(int x)
{
this->val = x;
next = NULL;
}
};
struct node *head = new node(3);
head -> next = new node(4); // error: head does not name a type.
head -> next->next = new node(5); // error: head does not name a type.
void print(){
struct node* temp = head;
while (temp != NULL) {
cout << temp->val << " ";
temp = temp->next;
}
}
int main()
{
print();
return 0;
}
I cannot figure out why am i getting the error.我不知道为什么会收到错误消息。 Please someone help me out.请有人帮助我。
Only declarations are allowed outside of functions.只允许在函数外声明。 Expressions such as head->next = node(4)
need to be inside a function. You should move that code into main()
. head->next = node(4)
等表达式需要在 function 中。您应该将该代码移至main()
中。
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