[英]Deep copy constructor in C++
The program is aimed to create a deep copy constructor for Foo.该程序旨在为 Foo 创建一个深拷贝构造函数。 Here's the class definition:
这是 class 的定义:
class Foo {
int _cSize;
char *_cValues;
std::vector<int> _iValues;
double _dValues[100];
public:
double &dValues(int i) { return _dValues[i]; }
int &iValues(int i) { return _iValues[i]; }
char &cValues(int i) { return _cValues[i]; }
int cSize(void) const { return _cSize; }
Foo(void) : _cSize(100), _cValues(new char[_cSize]) {}
};
and here's the implementation of copy constructor:这是复制构造函数的实现:
Foo &Foo::operator=(const Foo& foo) {
_cSize = foo._cSize;
_cValues = new char [_cSize];
for (int i = 0; i < _cSize; i++) {
_cValues[i] = foo._cValues[i];
}
_iValues = foo._iValues;
for (int i = 0; i < 100; i++) {
_dValues[i] = foo._dValues[i];
}
return *this;
}
However, the operator=
is showing an error that "Definition of implicitly declared copy assignment operator".但是,
operator=
显示错误“隐式声明的复制赋值运算符的定义”。 Any suggestions on how to fix the copy constructor?关于如何修复复制构造函数的任何建议?
Copy constructors are like复制构造函数就像
class Foo {
// ...
public:
Foo(const Foo& op) {
// copy fields
}
};
note that they are constructors just like Foo(void) you declared, but they have one param that's a const reference.请注意,它们就像您声明的 Foo(void) 一样是构造函数,但它们有一个参数,即 const 引用。
See also: Copy constructor and = operator overload in C++: is a common function possible?另请参阅: C++ 中的复制构造函数和 = 运算符重载:常见的 function 可能吗?
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