第二个变量如何在“for i, j in enumerate”与 list[i] 中工作

Question

I understand that it is for 'index', 'value' in enumerate, I thought that I could use the second variable as list[index] but it doesn't seem to work as such, I was wondering what the difference was.

codeCopy = [1,2,1,1]
currentSequence = [2,1,2,2]
correctColor = 0

for i, n in enumerate(codeCopy):
    for a, b in enumerate(currentSequence):
        if n == b:
            correctColor += 1
            n = None
            b = None
            print("i:",i, a)
            break
            
print(currentSequence)
print(codeCopy)

which outputs their original values instead of their new value of 'None' but if I replace

n = None
b = None

to

codeCopy[i] = None
currentSequence[a] = None

It turns them accordingly to 'None'

Answer 1

which outputs their original values instead of their new value of 'none'

It's not supposed to do that. The values n and b , as returned by enumerate , are pointers to the objects, but setting them to None only changes what those variable names reference, rather than the actual object itself. (You'll have to use memcpy -type magic to achieve this.)

Think of it like this:

>>> a = ['my', 'reference', 'to', 'a', 'list']
>>> b = a
>>> b[0] = 'this also changes a'  # b references the same object at a
>>> a
['this also changes a', 'reference', 'to', 'a', 'list']
>>> b = None  # this overwrites what b points to; it does not affect a
>>> a
['this also changes a', 'reference', 'to', 'a', 'list']

Suppose the program, in memory, looks like this:

address | value
100     | ['my', 'reference', 'to', 'a', 'list']  
101     | a -> 100 (list)
102     | b -> 100 (list)

When you change b , it doesn't actually affect the actual object:

address | value
100     | ['my', 'reference', 'to', 'a', 'list']  
101     | a -> 100 (list)
102     | b -> 103 (None)  # does NOT set the value at 100 to None
103     | None  # implementation detail: small integers and None and other things are permanently kept somewhere in memory at initialization

If you want to modify the value that's actually at the list, you need to do the_list[desired_index] = None .

Answer 2

from https://docs.python.org/3/library/functions.html#enumerate

Equivalent to:

 def enumerate(sequence, start=0): n = start for elem in sequence: yield n, elem n += 1