Python：如何打印for循环的output？

Question

I have this code

x = random.randint(0,1)
y = 100
for x in range(y):

What's now? How do I print the output? I tried printing x but it didn't work.

Answer 1

x = random.randint(0,1) 
y = 100 
for x in range(y):
    print(x)

I'm not sure if it is what you wanted

Answer 2

Maybe this? To print y random integer between 0 and 1.

y = 100
for i in range(y):
    x = random.randint(0,1)
    print(x)

Answer 3

@DragonPeti "Thx? Is there a way that I can print x into a single line or string because this way python prints just one number in a line?"

y = 100 
for a in range(y):
    print(random.randint(0,1),end='')

OUTPUT

1100000000001101010100100011010100010000000101000111100011101101001011000100001100111000011111001000

# OR Changing end='' to end=' '

1 1 1 0 0 1 1 1 1 1 0 0 1 0 1 1 1 1 0 1 1 0 1 0 0 1 1 0 1 1 0 0 1 1 1 0 1 1 0 0 1 1 0 0 1 1 0 0 1 0 1 1 1 0 0 0 1 1 0 0 1 1 0 1 0 1 1 1 0 1 0 1 0 1 1 1 0 1 0 1 0 0 0 1 1 1 1 1 1 0 0 0 1 0 1 0 1 0 1 0 

Answer 4

The reason you don't get a random number between 0 and 1 for each iteration of the for loop is because

1. You have overwritten the value of x at for x in , and

2. You did not redefine x to be a random number in the loop, so even if you were to remove the part that overwrites x , it will remain the same number throughout the loop.

This is what you want:

y = 100
for _ in range(y):
    x = random.randint(0,1)
    print(x)

With the above, you can replace the _ with x and it will not be affected, but it's better practice to use _ when iterating though an iterable with ever using the values within the iterable.