[英]C# XmlSerializer de-serialize abstract class without knowing concrete class
I would like to deserialize xml where the root class is an Abstract class but the root node in the xml has a value of the XML root attribute in the concrete class. The key is to do this without specifying the concrete class to deserialize in the XmlSerializer
constructor. I would like to deserialize xml where the root class is an Abstract class but the root node in the xml has a value of the XML root attribute in the concrete class. The key is to do this without specifying the concrete class to deserialize in the XmlSerializer
构造函数。
Example:例子:
MessageType.cs MessageType.cs
[Serializable]
[XmlInclude(typeof(Entity))]
public abstract class MessageType
{
}
Entity.cs实体.cs
[Serializable]
[XmlRoot("Entity", IsNullable = false)]
public class Entity : MessageType
{
private string data;
public string Data
{
get { return data; }
set { data = value; }
}
}
Program.cs程序.cs
var entity = new Entity
{
Data = "test"
};
var xs = new XmlSerializer(typeof(Entity));
using var stream = new System.IO.StringWriter();
xs.Serialize(stream, entity);
var xml = stream.ToString();
using var stringReader = new System.IO.StringReader(xml);
xs = new XmlSerializer(typeof(MessageType));
var obj = serializer.Deserialize(stringReader);
This code results in此代码导致
Unhandled exception. System.InvalidOperationException: There is an error in XML document (2, 2).
---> System.InvalidOperationException: <Entity xmlns=''> was not expected.
at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderMessageType.Read4_MessageType()
--- End of inner exception stack trace ---
at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events)
at System.Xml.Serialization.XmlSerializer.Deserialize(TextReader textReader)
The xml produced by the serialization in the code above looks like:上面代码中序列化产生的 xml 如下所示:
<?xml version="1.0" encoding="utf-16"?>
<Entity xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Data>test</Data>
</Entity>
Couple Extra Notes:夫妇额外注意事项:
MessageType
class and with xml deserialization seeming to be a slow process, looping over each possible type and seeing if it can deserialize is not ideal有很多MessageType
class 的具体 class 实现和 xml 反序列化似乎是一个缓慢的过程,遍历每种可能的类型并查看它是否可以反序列化并不理想<?xml version="1.0" encoding="utf-16"?> <MessageType xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xsi:type="Entity"> <Data>test</Data> </MessageType>
that it would work, but refer to note #1.它会起作用,但请参阅注释 #1。You can get the name of the root node with the XmlReader.您可以使用 XmlReader 获取根节点的名称。 Then you can get the type by name and create the serializer accordingly.然后您可以通过名称获取类型并相应地创建序列化程序。
using var xmlReader = XmlReader.Create(stream);
xmlReader.MoveToContent();
var rootNodeName = xmlReader.Name;
var implementationType = Type.GetType(rootNodeName);
if (implementationType != null)
{
var serializer = new XmlSerializer(implementationType);
var obj = serializer.Deserialize(xmlReader);
}
else
{
// unknown type
}
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