JavaScript：将文本中的单词与数组中的单词匹配并替换它

Question

I need to change this text:

var text = `this is an example text. 1coffee , 2 coffee , 1 apple, 2apple , ?banana ,carrot`;

using these 2 arrays :

var arrOld = ["coffee", "apple", "banana" , "carrot"];
var arrnew = ["laptop", "keyboard", "mouse", "printer"];

to get result like this:

`this is an example text. 1laptop , 2 laptop , 1 keyboard, 2keyboard , ?mouse ,printer`

I was trying something like:

for (let i = 0; i < arrOld.length; i++) {
arrNew[i];
arrOld[i];
text.replace(arrOld[i],arrNew[i])
}

but it didn't work.

Answer 1

From the docs on .replace ( https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace ):
"The replace() method returns a new string with some or all matches of a pattern replaced by a replacement."
This means that text.replace() doesn't manipulate the text variable. To fix this, simply do the following in your loop:
text = text.replace()
This will catch the changed text into the text variable. Without doing this, you are making the changes, but you are not using them (you forget them).

Answer 2

You could use String.prototype. :

 var text = "this is an example text. 1coffee , 2 coffee , 1 apple, 2apple , ?banana ,carrot"; var arrOld = ["coffee", "apple", "banana", "carrot"]; var arrnew = ["laptop", "keyboard", "mouse", "printer"] for (let i = 0; i < arrOld.length; i++) { text = text.replaceAll(arrOld[i], arrnew[i]); } console.log(text);

And maybe also Array.prototype. :

 var text = "this is an example text. 1coffee , 2 coffee , 1 apple, 2apple , ?banana ,carrot"; var arrOld = ["coffee", "apple", "banana", "carrot"]; var arrnew = ["laptop", "keyboard", "mouse", "printer"]; arrOld.map((old, i) => text = text.replaceAll(old, arrnew[i])); console.log(text);

Answer 3

replace returns a new string instead of changing the old one

you can use reduce

also add RegExp because replace works only for the first match it found

 const text = `this is an example text. 1coffee , 2 coffee , 1 apple, 2apple , ?banana, another banana ,carrot`; var arrOld = ["coffee", "apple", "banana" , "carrot"]; var arrnew = ["laptop", "keyboard", "mouse", "printer"]; const resultWitoutRegexp = arrOld.reduce((res, textToChange, i) => res.replace(textToChange, arrnew[i]) , text) const result = arrOld.reduce((res, textToChange, i) => res.replace(new RegExp(textToChange, 'g'), arrnew[i]) , text) console.log(resultWitoutRegexp) console.log(result)

Answer 4

You can try this. Modified from your code.

 const oldArray = ["coffee", "apple", "banana" , "carrot"]; const newArray = ["laptop", "keyboard", "mouse", "printer"]; let text = `this is an example text. 1coffee , 2 coffee , 1 apple, 2apple , ?banana ,carrot`; const { length } = oldArray for (let i = 0; i < length; i++) { text = text.replace(oldArray[i], newArray[i]); } console.log(text);